Sabrina had 18 more sweets than Andy at first. After Andy had eaten 10 of his sweets, Sabrina had 5 times as many sweets as Andy. How many sweets did Sabrina and Andy have in total at first?
| |
Sabrina |
Andy |
Total |
| Before |
1 u + 10 + 18 |
1 u + 10 |
6 u + 10 |
| Change |
|
- 10 |
|
| After |
5 u |
1 u |
|
The number of sweets that Sabrina had at first remains unchanged.
5 u = 1 u + 10 + 18
5 u - 1 u = 28
4 u = 28
1 u = 28 ÷ 4 = 7
Number of sweets that they had at first
= 6 u + 10
= 6 x 7 + 10
= 42 + 10
= 52
Answer(s): 52
