Last Thursday, Lee had thrice as many beads as Oscar. Today, Lee gives 110 of his beads to his buddy. Now, Oscar has four times as many beads as Lee. How many beads does Oscar have?
| |
Lee |
Oscar |
| Before |
3x4 =
12 u |
1x4 =
4 u |
| Change |
- 110 |
|
| After |
1 u |
4 u |
The number of beads that Oscar had at first and in the end remains unchanged. Make the number of beads that Oscar has the same. LCM of 1 and 4 is 4.
Number of beads that Lee gives to his buddy
= 12 u - 1 u
= 11 u
11 u = 110
1 u = 110 ÷ 11 = 10
Number of beads that Oscar has
= 4 u
= 4 x 10
= 40
Answer(s): 40
