Last Friday, Luis had thrice as many beads as Xavier. Today, Luis gives 35 of his beads to his buddy. Now, Xavier has twice as many beads as Luis. How many beads does Xavier have?
| |
Luis |
Xavier |
| Before |
3x2 =
6 u |
1x2 =
2 u |
| Change |
- 35 |
|
| After |
1 u |
2 u |
The number of beads that Xavier had at first and in the end remains unchanged. Make the number of beads that Xavier has the same. LCM of 1 and 2 is 2.
Number of beads that Luis gives to his buddy
= 6 u - 1 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of beads that Xavier has
= 2 u
= 2 x 7
= 14
Answer(s): 14
