Last Tuesday, Albert had twice as many coins as Julian. Today, Albert gives 28 of his coins to his best friend. Now, Julian has four times as many coins as Albert. How many coins does Julian have?
| |
Albert |
Julian |
| Before |
2x4 =
8 u |
1x4 =
4 u |
| Change |
- 28 |
|
| After |
1 u |
4 u |
The number of coins that Julian had at first and in the end remains unchanged. Make the number of coins that Julian has the same. LCM of 1 and 4 is 4.
Number of coins that Albert gives to his best friend
= 8 u - 1 u
= 7 u
7 u = 28
1 u = 28 ÷ 7 = 4
Number of coins that Julian has
= 4 u
= 4 x 4
= 16
Answer(s): 16
