Last Wednesday, Vincent had twice as many beads as Ahmad. Today, Vincent gives 77 of his beads to his brother. Now, Ahmad has four times as many beads as Vincent. How many beads does Ahmad have?
| |
Vincent |
Ahmad |
| Before |
2x4 =
8 u |
1x4 =
4 u |
| Change |
- 77 |
|
| After |
1 u |
4 u |
The number of beads that Ahmad had at first and in the end remains unchanged. Make the number of beads that Ahmad has the same. LCM of 1 and 4 is 4.
Number of beads that Vincent gives to his brother
= 8 u - 1 u
= 7 u
7 u = 77
1 u = 77 ÷ 7 = 11
Number of beads that Ahmad has
= 4 u
= 4 x 11
= 44
Answer(s): 44
