Yesterday, there were thrice as many cows as chickens on a farm. Today, 50 cows are sold. There are twice as many chickens now. Find the total number of chickens and cows on the farm yesterday.
| |
Cows |
Chickens |
Total |
| Before |
3x2 =
6 u |
1x2 =
2 u |
8 u |
| Change |
- 50 |
|
|
| After |
1 u |
2 u |
|
The number of chickens at first and in the end remains unchanged. Make the number of chickens the same. LCM of 1 and 2 is 2.
Number of cows sold
= 6 u - 1 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Total number of chickens and cows yesterday
= 6 u + 2 u
= 8 u
= 8 x 10
= 80
Answer(s): 80
