Yesterday, there were twice as many cows as pigs on a farm. Today, 35 cows are sold. There are thrice as many pigs now. Find the total number of pigs and cows on the farm yesterday.
| |
Cows |
Pigs |
Total |
| Before |
2x3 =
6 u |
1x3 =
3 u |
9 u |
| Change |
- 35 |
|
|
| After |
1 u |
3 u |
|
The number of pigs at first and in the end remains unchanged. Make the number of pigs the same. LCM of 1 and 3 is 3.
Number of cows sold
= 6 u - 1 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Total number of pigs and cows yesterday
= 6 u + 3 u
= 9 u
= 9 x 7
= 63
Answer(s): 63
