Yesterday, there were twice as many goats as chickens on a farm. Today, 15 goats are sold. There are thrice as many chickens now. Find the total number of chickens and goats on the farm yesterday.
| |
Goats |
Chickens |
Total |
| Before |
2x3 =
6 u |
1x3 =
3 u |
9 u |
| Change |
- 15 |
|
|
| After |
1 u |
3 u |
|
The number of chickens at first and in the end remains unchanged. Make the number of chickens the same. LCM of 1 and 3 is 3.
Number of goats sold
= 6 u - 1 u
= 5 u
5 u = 15
1 u = 15 ÷ 5 = 3
Total number of chickens and goats yesterday
= 6 u + 3 u
= 9 u
= 9 x 3
= 27
Answer(s): 27
