Yesterday, there were four times as many sheep as cows on a farm. Today, 55 sheep are sold. There are thrice as many cows now. Find the total number of cows and sheep on the farm yesterday.
|
Sheep |
Cows |
Total |
Before |
4x3 = 12 u |
1x3 = 3 u |
15 u |
Change |
- 55 |
|
|
After |
1 u |
3 u |
|
The number of cows at first and in the end remains unchanged. Make the number of cows the same. LCM of 1 and 3 is 3.
Number of sheep sold
= 12 u - 1 u
= 11 u
11 u = 55
1 u = 55 ÷ 11 = 5
Total number of cows and sheep yesterday
= 12 u + 3 u
= 15 u
= 15 x 5
= 75
Answer(s): 75