Oscar has 6 boxes and 2 bags of coins. He has a total of 68 coins. Each bag contains 6 more coins than each box. How many coins are there in each bag?
|
Boxes |
Bags |
Total |
Number |
6 |
2 |
|
Value |
1 u |
1 u + 6 |
|
Total value |
6 u |
2 u + 12 |
8 u + 12 |
Number of coins in each box = 1 u
Number of coins in each bag = 1 u + 6
Total number of coins in the boxes = 6 x 1 u = 6 u
Total number of coins in the bags = 2(1 u + 6) = 2 u + 12
Total number of coins
= 2 u + 6 u + 12
= 8 u + 12
8 u + 12 = 68
8 u = 68 - 12
8 u = 56
1 u = 56 ÷ 8 = 7
Number of coins in each bag
= 1 u + 6
= 7 + 6
= 13
Answer(s): 13