Julian has 5 boxes and 3 bags of coins. He has a total of 99 coins. Each bag contains 9 more coins than each box. How many coins are there in each bag?
| |
Boxes |
Bags |
Total |
| Number |
5 |
3 |
|
| Value |
1 u |
1 u + 9 |
|
| Total value |
5 u |
3 u + 27 |
8 u + 27 |
Number of coins in each box = 1 u
Number of coins in each bag = 1 u + 9
Total number of coins in the boxes = 5 x 1 u = 5 u
Total number of coins in the bags = 3(1 u + 9) = 3 u + 27
Total number of coins
= 3 u + 5 u + 27
= 8 u + 27
8 u + 27 = 99
8 u = 99 - 27
8 u = 72
1 u = 72 ÷ 8 = 9
Number of coins in each bag
= 1 u + 9
= 9 + 9
= 18
Answer(s): 18
