Ken has 4 boxes and 5 packets of coins. He has a total of 93 coins. Each packet contains 6 more coins than each box. How many coins are there in each packet?
|
Boxes |
Packets |
Total |
Number |
4 |
5 |
|
Value |
1 u |
1 u + 6 |
|
Total value |
4 u |
5 u + 30 |
9 u + 30 |
Number of coins in each box = 1 u
Number of coins in each packet = 1 u + 6
Total number of coins in the boxes = 4 x 1 u = 4 u
Total number of coins in the packets = 5(1 u + 6) = 5 u + 30
Total number of coins
= 5 u + 4 u + 30
= 9 u + 30
9 u + 30 = 93
9 u = 93 - 30
9 u = 63
1 u = 63 ÷ 9 = 7
Number of coins in each packet
= 1 u + 6
= 7 + 6
= 13
Answer(s): 13