There are 5 badminton players. Each player will have one match against each of the other 4 players. How many different matches are there to be arranged?
| |
Player 1 |
Player 2 |
Player 3 |
Player 4 |
| Player 1 |
x |
✓ |
✓ |
✓ |
| Player 2 |
x |
x |
✓ |
✓ |
| Player 3 |
x |
x |
x |
✓ |
| Player 4 |
x |
x |
x |
x |
Each badminton player only plays with each of the other badminton players once.
Number of matches based on number of badminton players:
2 players:
1 =
2 x 123 players:
1 + 2 = 3 =
3 x 224 players:
1 + 2 + 3 = 6 =
4 x 32Formula:
Number of matches =
Number of players x (Number of players - 1)2Number of matches arranged for 5 badminton players
=
5 x 42= 10
Answer(s): 10
