Betty had some coins at first. She gave 29 of her coins to her sister and 16 of her coins to her neighbour. After that, her mother gave her another 8 coins. She had 85 coins in the end. How many coins did Betty have at first?
Fraction of coins left after giving to her sister and her neighbour
= 1 -
29 -
16 = 1 -
418 -
318 = 1 -
718 =
1118 Number of coins left after giving to her sister and her neighbour = 11 u
Number of coins left after her mother gave her another 8 coins = 11 u + 8
11 u + 8 = 85
11 u = 85 - 8
11 u = 77
1 u = 77 ÷ 11 = 7
Number of coins that Betty had at first
= 18 u
= 18 x 7
= 126
Answer(s): 126
