At the end of November, Jade had twice as many 20-cent coins as 50-cent coins in her piggy bank. She took out 65 20-cent coins and exchanged it for 50-cent coins of the same value. In December, she saved another 29 20-cent coins and some 50-cent coins. She then had four times as many 50-cent coins in the end. She had 250 coins in the end. How many 50-cent coins did she save in December?
|
20-cent |
50-cent |
Total |
Before |
2 u |
1 u |
|
Change 1 |
- 65 |
+ 26 |
|
Change 2 |
+ 29 |
+ ? |
|
After |
1 p |
4 p |
250 |
Total number of coins in the end
= 1 p + 4 p
= 5 p
5 p = 250
1 p = 250 ÷ 5 = 50
Number of 20-cent in the end
= 1 p
= 50
Number of 20-cent at first
= 50 - 29 + 65
= 86
2 u = 86
1 u = 86 ÷ 2 = 43
Number of 50-cent coins in the end
= 4 p
= 4 x 50
= 200
Total value of 65 20-cent coins
= 65 x 20
= 1300¢
Number of 50-cent coins that was exchanged from 65 20-cent coins
= 1300 ÷ 50
= 26
Number of 50-cent coins that Jade saved in December
= 4 p - 1 u - 26
= 200 - 43 - 26
= 131
Answer(s): 131