Marion had five times as many pens as pencils. After giving away 64 pens and selling 18 pens, she found out that she had four times as many pens as pencils left.
- How many pens did Marion have at first?
- How many pens and pencils did Marion have altogether at first?
|
Pens |
Pencils |
Total |
Before |
5 u |
1 u |
6 u |
Change 1 |
- 64 |
|
- 1 u |
Change 2 |
- 18 |
|
After |
4 u |
1 u |
5 u |
(a)
The number of pencils remains unchanged.
Number of pens that Marion gave away or sold
= 5 u - 4 u
= 1 u
1 u = 64 + 18 = 82
Number of pens that Marion had at first
= 5 u
= 5 x 82
= 410
(b)
Total number of pens and pencils that Marion had at first
= 1 u + 5 u
= 6 u
= 6 x 82
= 492
Answer(s): (a) 410; (b) 492