Luis bought 32 more buttons than Howard and Howard bought 17 buttons more than Erika. The total number of buttons Luis and Howard bought was 4 times the number of buttons Erika bought.
- How many buttons does Luis need to give Howard so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
Luis |
Howard |
Erika |
1 u + 17 + 32 |
1 u + 17 |
1 u |
4 u |
1 u |
(a)
Number of buttons that Luis needs to give Howard so that they have same number of buttons
= 32 ÷ 2
= 16
(b)
Total number of buttons that Luis and Howard had
= 1 u + 17 + 32 + 1 u + 17
= 1 u + 1 u + 17 + 32 + 17
= 2 u + 66
4 u = 2 u + 66
4 u - 2 u = 66
2 u = 66
1 u = 66 ÷ 2 = 33
Total number of buttons that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 33
= 165
Answer(s): (a) 16; (b) 165