Luis bought 74 more coins than Seth and Seth bought 28 coins more than Penelope. The total number of coins Luis and Seth bought was 4 times the number of coins Penelope bought.
- How many coins does Luis need to give Seth so that they have the same number of coins?
- How many coins did all three of them have altogether?
Luis |
Seth |
Penelope |
1 u + 28 + 74 |
1 u + 28 |
1 u |
4 u |
1 u |
(a)
Number of coins that Luis needs to give Seth so that they have same number of coins
= 74 ÷ 2
= 37
(b)
Total number of coins that Luis and Seth had
= 1 u + 28 + 74 + 1 u + 28
= 1 u + 1 u + 28 + 74 + 28
= 2 u + 130
4 u = 2 u + 130
4 u - 2 u = 130
2 u = 130
1 u = 130 ÷ 2 = 65
Total number of coins that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 65
= 325
Answer(s): (a) 37; (b) 325