Perry bought 74 more erasers than Reggie and Reggie bought 27 erasers more than Min. The total number of erasers Perry and Reggie bought was 4 times the number of erasers Min bought.
- How many erasers does Perry need to give Reggie so that they have the same number of erasers?
- How many erasers did all three of them have altogether?
Perry |
Reggie |
Min |
1 u + 27 + 74 |
1 u + 27 |
1 u |
4 u |
1 u |
(a)
Number of erasers that Perry needs to give Reggie so that they have same number of erasers
= 74 ÷ 2
= 37
(b)
Total number of erasers that Perry and Reggie had
= 1 u + 27 + 74 + 1 u + 27
= 1 u + 1 u + 27 + 74 + 27
= 2 u + 128
4 u = 2 u + 128
4 u - 2 u = 128
2 u = 128
1 u = 128 ÷ 2 = 64
Total number of erasers that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 64
= 320
Answer(s): (a) 37; (b) 320