Oscar bought 36 more coins than Albert and Albert bought 24 coins more than Min. The total number of coins Oscar and Albert bought was 6 times the number of coins Min bought.
- How many coins does Oscar need to give Albert so that they have the same number of coins?
- How many coins did all three of them have altogether?
Oscar |
Albert |
Min |
1 u + 24 + 36 |
1 u + 24 |
1 u |
6 u |
1 u |
(a)
Number of coins that Oscar needs to give Albert so that they have same number of coins
= 36 ÷ 2
= 18
(b)
Total number of coins that Oscar and Albert had
= 1 u + 24 + 36 + 1 u + 24
= 1 u + 1 u + 24 + 36 + 24
= 2 u + 84
6 u = 2 u + 84
6 u - 2 u = 84
4 u = 84
1 u = 84 ÷ 4 = 21
Total number of coins that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 21
= 147
Answer(s): (a) 18; (b) 147