Eric bought 32 more cards than Howard and Howard bought 19 cards more than Opal. The total number of cards Eric and Howard bought was 4 times the number of cards Opal bought.
- How many cards does Eric need to give Howard so that they have the same number of cards?
- How many cards did all three of them have altogether?
Eric |
Howard |
Opal |
1 u + 19 + 32 |
1 u + 19 |
1 u |
4 u |
1 u |
(a)
Number of cards that Eric needs to give Howard so that they have same number of cards
= 32 ÷ 2
= 16
(b)
Total number of cards that Eric and Howard had
= 1 u + 19 + 32 + 1 u + 19
= 1 u + 1 u + 19 + 32 + 19
= 2 u + 70
4 u = 2 u + 70
4 u - 2 u = 70
2 u = 70
1 u = 70 ÷ 2 = 35
Total number of cards that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 35
= 175
Answer(s): (a) 16; (b) 175