Oscar bought 62 more beads than Pierre and Pierre bought 16 beads more than Sabrina. The total number of beads Oscar and Pierre bought was 4 times the number of beads Sabrina bought.
- How many beads does Oscar need to give Pierre so that they have the same number of beads?
- How many beads did all three of them have altogether?
Oscar |
Pierre |
Sabrina |
1 u + 16 + 62 |
1 u + 16 |
1 u |
4 u |
1 u |
(a)
Number of beads that Oscar needs to give Pierre so that they have same number of beads
= 62 ÷ 2
= 31
(b)
Total number of beads that Oscar and Pierre had
= 1 u + 16 + 62 + 1 u + 16
= 1 u + 1 u + 16 + 62 + 16
= 2 u + 94
4 u = 2 u + 94
4 u - 2 u = 94
2 u = 94
1 u = 94 ÷ 2 = 47
Total number of beads that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 47
= 235
Answer(s): (a) 31; (b) 235