Jenson bought 30 more pens than Charlie and Charlie bought 21 pens more than Yoko. The total number of pens Jenson and Charlie bought was 6 times the number of pens Yoko bought.
- How many pens does Jenson need to give Charlie so that they have the same number of pens?
- How many pens did all three of them have altogether?
Jenson |
Charlie |
Yoko |
1 u + 21 + 30 |
1 u + 21 |
1 u |
6 u |
1 u |
(a)
Number of pens that Jenson needs to give Charlie so that they have same number of pens
= 30 ÷ 2
= 15
(b)
Total number of pens that Jenson and Charlie had
= 1 u + 21 + 30 + 1 u + 21
= 1 u + 1 u + 21 + 30 + 21
= 2 u + 72
6 u = 2 u + 72
6 u - 2 u = 72
4 u = 72
1 u = 72 ÷ 4 = 18
Total number of pens that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 18
= 126
Answer(s): (a) 15; (b) 126