Howard bought 62 more marbles than Bobby and Bobby bought 11 marbles more than Irene. The total number of marbles Howard and Bobby bought was 6 times the number of marbles Irene bought.
- How many marbles does Howard need to give Bobby so that they have the same number of marbles?
- How many marbles did all three of them have altogether?
Howard |
Bobby |
Irene |
1 u + 11 + 62 |
1 u + 11 |
1 u |
6 u |
1 u |
(a)
Number of marbles that Howard needs to give Bobby so that they have same number of marbles
= 62 ÷ 2
= 31
(b)
Total number of marbles that Howard and Bobby had
= 1 u + 11 + 62 + 1 u + 11
= 1 u + 1 u + 11 + 62 + 11
= 2 u + 84
6 u = 2 u + 84
6 u - 2 u = 84
4 u = 84
1 u = 84 ÷ 4 = 21
Total number of marbles that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 21
= 147
Answer(s): (a) 31; (b) 147