Pierre bought 40 more pens than Wesley and Wesley bought 22 pens more than Tiffany. The total number of pens Pierre and Wesley bought was 6 times the number of pens Tiffany bought.
- How many pens does Pierre need to give Wesley so that they have the same number of pens?
- How many pens did all three of them have altogether?
Pierre |
Wesley |
Tiffany |
1 u + 22 + 40 |
1 u + 22 |
1 u |
6 u |
1 u |
(a)
Number of pens that Pierre needs to give Wesley so that they have same number of pens
= 40 ÷ 2
= 20
(b)
Total number of pens that Pierre and Wesley had
= 1 u + 22 + 40 + 1 u + 22
= 1 u + 1 u + 22 + 40 + 22
= 2 u + 84
6 u = 2 u + 84
6 u - 2 u = 84
4 u = 84
1 u = 84 ÷ 4 = 21
Total number of pens that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 21
= 147
Answer(s): (a) 20; (b) 147