Ahmad bought 78 more coins than Cole and Cole bought 19 coins more than Dana. The total number of coins Ahmad and Cole bought was 4 times the number of coins Dana bought.
- How many coins does Ahmad need to give Cole so that they have the same number of coins?
- How many coins did all three of them have altogether?
Ahmad |
Cole |
Dana |
1 u + 19 + 78 |
1 u + 19 |
1 u |
4 u |
1 u |
(a)
Number of coins that Ahmad needs to give Cole so that they have same number of coins
= 78 ÷ 2
= 39
(b)
Total number of coins that Ahmad and Cole had
= 1 u + 19 + 78 + 1 u + 19
= 1 u + 1 u + 19 + 78 + 19
= 2 u + 116
4 u = 2 u + 116
4 u - 2 u = 116
2 u = 116
1 u = 116 ÷ 2 = 58
Total number of coins that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 58
= 290
Answer(s): (a) 39; (b) 290