Oliver bought 66 more coins than Peter and Peter bought 16 coins more than Risa. The total number of coins Oliver and Peter bought was 4 times the number of coins Risa bought.
- How many coins does Oliver need to give Peter so that they have the same number of coins?
- How many coins did all three of them have altogether?
Oliver |
Peter |
Risa |
1 u + 16 + 66 |
1 u + 16 |
1 u |
4 u |
1 u |
(a)
Number of coins that Oliver needs to give Peter so that they have same number of coins
= 66 ÷ 2
= 33
(b)
Total number of coins that Oliver and Peter had
= 1 u + 16 + 66 + 1 u + 16
= 1 u + 1 u + 16 + 66 + 16
= 2 u + 98
4 u = 2 u + 98
4 u - 2 u = 98
2 u = 98
1 u = 98 ÷ 2 = 49
Total number of coins that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 49
= 245
Answer(s): (a) 33; (b) 245