Pierre bought 64 more cards than Liam and Liam bought 17 cards more than Xuan. The total number of cards Pierre and Liam bought was 4 times the number of cards Xuan bought.
- How many cards does Pierre need to give Liam so that they have the same number of cards?
- How many cards did all three of them have altogether?
Pierre |
Liam |
Xuan |
1 u + 17 + 64 |
1 u + 17 |
1 u |
4 u |
1 u |
(a)
Number of cards that Pierre needs to give Liam so that they have same number of cards
= 64 ÷ 2
= 32
(b)
Total number of cards that Pierre and Liam had
= 1 u + 17 + 64 + 1 u + 17
= 1 u + 1 u + 17 + 64 + 17
= 2 u + 98
4 u = 2 u + 98
4 u - 2 u = 98
2 u = 98
1 u = 98 ÷ 2 = 49
Total number of cards that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 49
= 245
Answer(s): (a) 32; (b) 245