Howard bought 52 more marbles than Rael and Rael bought 20 marbles more than Xuan. The total number of marbles Howard and Rael bought was 4 times the number of marbles Xuan bought.
- How many marbles does Howard need to give Rael so that they have the same number of marbles?
- How many marbles did all three of them have altogether?
Howard |
Rael |
Xuan |
1 u + 20 + 52 |
1 u + 20 |
1 u |
4 u |
1 u |
(a)
Number of marbles that Howard needs to give Rael so that they have same number of marbles
= 52 ÷ 2
= 26
(b)
Total number of marbles that Howard and Rael had
= 1 u + 20 + 52 + 1 u + 20
= 1 u + 1 u + 20 + 52 + 20
= 2 u + 92
4 u = 2 u + 92
4 u - 2 u = 92
2 u = 92
1 u = 92 ÷ 2 = 46
Total number of marbles that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 46
= 230
Answer(s): (a) 26; (b) 230