David bought 40 more pens than Andy and Andy bought 14 pens more than Abi. The total number of pens David and Andy bought was 6 times the number of pens Abi bought.
- How many pens does David need to give Andy so that they have the same number of pens?
- How many pens did all three of them have altogether?
David |
Andy |
Abi |
1 u + 14 + 40 |
1 u + 14 |
1 u |
6 u |
1 u |
(a)
Number of pens that David needs to give Andy so that they have same number of pens
= 40 ÷ 2
= 20
(b)
Total number of pens that David and Andy had
= 1 u + 14 + 40 + 1 u + 14
= 1 u + 1 u + 14 + 40 + 14
= 2 u + 68
6 u = 2 u + 68
6 u - 2 u = 68
4 u = 68
1 u = 68 ÷ 4 = 17
Total number of pens that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 17
= 119
Answer(s): (a) 20; (b) 119