Ken bought 70 more buttons than Will and Will bought 28 buttons more than Jaslyn. The total number of buttons Ken and Will bought was 4 times the number of buttons Jaslyn bought.
- How many buttons does Ken need to give Will so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
Ken |
Will |
Jaslyn |
1 u + 28 + 70 |
1 u + 28 |
1 u |
4 u |
1 u |
(a)
Number of buttons that Ken needs to give Will so that they have same number of buttons
= 70 ÷ 2
= 35
(b)
Total number of buttons that Ken and Will had
= 1 u + 28 + 70 + 1 u + 28
= 1 u + 1 u + 28 + 70 + 28
= 2 u + 126
4 u = 2 u + 126
4 u - 2 u = 126
2 u = 126
1 u = 126 ÷ 2 = 63
Total number of buttons that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 63
= 315
Answer(s): (a) 35; (b) 315