Charlie bought 30 more stamps than Paul and Paul bought 11 stamps more than Shiyun. The total number of stamps Charlie and Paul bought was 6 times the number of stamps Shiyun bought.
- How many stamps does Charlie need to give Paul so that they have the same number of stamps?
- How many stamps did all three of them have altogether?
Charlie |
Paul |
Shiyun |
1 u + 11 + 30 |
1 u + 11 |
1 u |
6 u |
1 u |
(a)
Number of stamps that Charlie needs to give Paul so that they have same number of stamps
= 30 ÷ 2
= 15
(b)
Total number of stamps that Charlie and Paul had
= 1 u + 11 + 30 + 1 u + 11
= 1 u + 1 u + 11 + 30 + 11
= 2 u + 52
6 u = 2 u + 52
6 u - 2 u = 52
4 u = 52
1 u = 52 ÷ 4 = 13
Total number of stamps that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 13
= 91
Answer(s): (a) 15; (b) 91