Bryan bought 60 more stickers than Pierre and Pierre bought 20 stickers more than Cindy. The total number of stickers Bryan and Pierre bought was 4 times the number of stickers Cindy bought.
- How many stickers does Bryan need to give Pierre so that they have the same number of stickers?
- How many stickers did all three of them have altogether?
Bryan |
Pierre |
Cindy |
1 u + 20 + 60 |
1 u + 20 |
1 u |
4 u |
1 u |
(a)
Number of stickers that Bryan needs to give Pierre so that they have same number of stickers
= 60 ÷ 2
= 30
(b)
Total number of stickers that Bryan and Pierre had
= 1 u + 20 + 60 + 1 u + 20
= 1 u + 1 u + 20 + 60 + 20
= 2 u + 100
4 u = 2 u + 100
4 u - 2 u = 100
2 u = 100
1 u = 100 ÷ 2 = 50
Total number of stickers that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 50
= 250
Answer(s): (a) 30; (b) 250