Paul bought 38 more cards than Wesley and Wesley bought 13 cards more than Rachel. The total number of cards Paul and Wesley bought was 4 times the number of cards Rachel bought.
- How many cards does Paul need to give Wesley so that they have the same number of cards?
- How many cards did all three of them have altogether?
Paul |
Wesley |
Rachel |
1 u + 13 + 38 |
1 u + 13 |
1 u |
4 u |
1 u |
(a)
Number of cards that Paul needs to give Wesley so that they have same number of cards
= 38 ÷ 2
= 19
(b)
Total number of cards that Paul and Wesley had
= 1 u + 13 + 38 + 1 u + 13
= 1 u + 1 u + 13 + 38 + 13
= 2 u + 64
4 u = 2 u + 64
4 u - 2 u = 64
2 u = 64
1 u = 64 ÷ 2 = 32
Total number of cards that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 32
= 160
Answer(s): (a) 19; (b) 160