David bought 66 more buttons than Jeremy and Jeremy bought 21 buttons more than Jean. The total number of buttons David and Jeremy bought was 6 times the number of buttons Jean bought.
- How many buttons does David need to give Jeremy so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
David |
Jeremy |
Jean |
1 u + 21 + 66 |
1 u + 21 |
1 u |
6 u |
1 u |
(a)
Number of buttons that David needs to give Jeremy so that they have same number of buttons
= 66 ÷ 2
= 33
(b)
Total number of buttons that David and Jeremy had
= 1 u + 21 + 66 + 1 u + 21
= 1 u + 1 u + 21 + 66 + 21
= 2 u + 108
6 u = 2 u + 108
6 u - 2 u = 108
4 u = 108
1 u = 108 ÷ 4 = 27
Total number of buttons that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 27
= 189
Answer(s): (a) 33; (b) 189