Wesley bought 56 more buttons than Tim and Tim bought 15 buttons more than Kimberly. The total number of buttons Wesley and Tim bought was 4 times the number of buttons Kimberly bought.
- How many buttons does Wesley need to give Tim so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
Wesley |
Tim |
Kimberly |
1 u + 15 + 56 |
1 u + 15 |
1 u |
4 u |
1 u |
(a)
Number of buttons that Wesley needs to give Tim so that they have same number of buttons
= 56 ÷ 2
= 28
(b)
Total number of buttons that Wesley and Tim had
= 1 u + 15 + 56 + 1 u + 15
= 1 u + 1 u + 15 + 56 + 15
= 2 u + 86
4 u = 2 u + 86
4 u - 2 u = 86
2 u = 86
1 u = 86 ÷ 2 = 43
Total number of buttons that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 43
= 215
Answer(s): (a) 28; (b) 215