Vincent bought 44 more cards than Michael and Michael bought 24 cards more than Min. The total number of cards Vincent and Michael bought was 6 times the number of cards Min bought.
- How many cards does Vincent need to give Michael so that they have the same number of cards?
- How many cards did all three of them have altogether?
Vincent |
Michael |
Min |
1 u + 24 + 44 |
1 u + 24 |
1 u |
6 u |
1 u |
(a)
Number of cards that Vincent needs to give Michael so that they have same number of cards
= 44 ÷ 2
= 22
(b)
Total number of cards that Vincent and Michael had
= 1 u + 24 + 44 + 1 u + 24
= 1 u + 1 u + 24 + 44 + 24
= 2 u + 92
6 u = 2 u + 92
6 u - 2 u = 92
4 u = 92
1 u = 92 ÷ 4 = 23
Total number of cards that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 23
= 161
Answer(s): (a) 22; (b) 161