Luis bought 78 more pens than Paul and Paul bought 28 pens more than Fanny. The total number of pens Luis and Paul bought was 4 times the number of pens Fanny bought.
- How many pens does Luis need to give Paul so that they have the same number of pens?
- How many pens did all three of them have altogether?
Luis |
Paul |
Fanny |
1 u + 28 + 78 |
1 u + 28 |
1 u |
4 u |
1 u |
(a)
Number of pens that Luis needs to give Paul so that they have same number of pens
= 78 ÷ 2
= 39
(b)
Total number of pens that Luis and Paul had
= 1 u + 28 + 78 + 1 u + 28
= 1 u + 1 u + 28 + 78 + 28
= 2 u + 134
4 u = 2 u + 134
4 u - 2 u = 134
2 u = 134
1 u = 134 ÷ 2 = 67
Total number of pens that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 67
= 335
Answer(s): (a) 39; (b) 335