Pierre bought 58 more buttons than Simon and Simon bought 11 buttons more than Erika. The total number of buttons Pierre and Simon bought was 6 times the number of buttons Erika bought.
- How many buttons does Pierre need to give Simon so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
Pierre |
Simon |
Erika |
1 u + 11 + 58 |
1 u + 11 |
1 u |
6 u |
1 u |
(a)
Number of buttons that Pierre needs to give Simon so that they have same number of buttons
= 58 ÷ 2
= 29
(b)
Total number of buttons that Pierre and Simon had
= 1 u + 11 + 58 + 1 u + 11
= 1 u + 1 u + 11 + 58 + 11
= 2 u + 80
6 u = 2 u + 80
6 u - 2 u = 80
4 u = 80
1 u = 80 ÷ 4 = 20
Total number of buttons that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 20
= 140
Answer(s): (a) 29; (b) 140