Ben bought 58 more buttons than Michael and Michael bought 15 buttons more than Opal. The total number of buttons Ben and Michael bought was 6 times the number of buttons Opal bought.
- How many buttons does Ben need to give Michael so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
Ben |
Michael |
Opal |
1 u + 15 + 58 |
1 u + 15 |
1 u |
6 u |
1 u |
(a)
Number of buttons that Ben needs to give Michael so that they have same number of buttons
= 58 ÷ 2
= 29
(b)
Total number of buttons that Ben and Michael had
= 1 u + 15 + 58 + 1 u + 15
= 1 u + 1 u + 15 + 58 + 15
= 2 u + 88
6 u = 2 u + 88
6 u - 2 u = 88
4 u = 88
1 u = 88 ÷ 4 = 22
Total number of buttons that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 22
= 154
Answer(s): (a) 29; (b) 154