Jack bought 56 more cards than Michael and Michael bought 22 cards more than Roshel. The total number of cards Jack and Michael bought was 6 times the number of cards Roshel bought.
- How many cards does Jack need to give Michael so that they have the same number of cards?
- How many cards did all three of them have altogether?
Jack |
Michael |
Roshel |
1 u + 22 + 56 |
1 u + 22 |
1 u |
6 u |
1 u |
(a)
Number of cards that Jack needs to give Michael so that they have same number of cards
= 56 ÷ 2
= 28
(b)
Total number of cards that Jack and Michael had
= 1 u + 22 + 56 + 1 u + 22
= 1 u + 1 u + 22 + 56 + 22
= 2 u + 100
6 u = 2 u + 100
6 u - 2 u = 100
4 u = 100
1 u = 100 ÷ 4 = 25
Total number of cards that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 25
= 175
Answer(s): (a) 28; (b) 175