Owen bought 52 more coins than Tim and Tim bought 27 coins more than Abi. The total number of coins Owen and Tim bought was 4 times the number of coins Abi bought.
- How many coins does Owen need to give Tim so that they have the same number of coins?
- How many coins did all three of them have altogether?
Owen |
Tim |
Abi |
1 u + 27 + 52 |
1 u + 27 |
1 u |
4 u |
1 u |
(a)
Number of coins that Owen needs to give Tim so that they have same number of coins
= 52 ÷ 2
= 26
(b)
Total number of coins that Owen and Tim had
= 1 u + 27 + 52 + 1 u + 27
= 1 u + 1 u + 27 + 52 + 27
= 2 u + 106
4 u = 2 u + 106
4 u - 2 u = 106
2 u = 106
1 u = 106 ÷ 2 = 53
Total number of coins that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 53
= 265
Answer(s): (a) 26; (b) 265