Warren bought 38 more erasers than George and George bought 28 erasers more than Min. The total number of erasers Warren and George bought was 4 times the number of erasers Min bought.
- How many erasers does Warren need to give George so that they have the same number of erasers?
- How many erasers did all three of them have altogether?
Warren |
George |
Min |
1 u + 28 + 38 |
1 u + 28 |
1 u |
4 u |
1 u |
(a)
Number of erasers that Warren needs to give George so that they have same number of erasers
= 38 ÷ 2
= 19
(b)
Total number of erasers that Warren and George had
= 1 u + 28 + 38 + 1 u + 28
= 1 u + 1 u + 28 + 38 + 28
= 2 u + 94
4 u = 2 u + 94
4 u - 2 u = 94
2 u = 94
1 u = 94 ÷ 2 = 47
Total number of erasers that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 47
= 235
Answer(s): (a) 19; (b) 235