Pierre bought 78 more erasers than Wesley and Wesley bought 21 erasers more than Risa. The total number of erasers Pierre and Wesley bought was 6 times the number of erasers Risa bought.
- How many erasers does Pierre need to give Wesley so that they have the same number of erasers?
- How many erasers did all three of them have altogether?
Pierre |
Wesley |
Risa |
1 u + 21 + 78 |
1 u + 21 |
1 u |
6 u |
1 u |
(a)
Number of erasers that Pierre needs to give Wesley so that they have same number of erasers
= 78 ÷ 2
= 39
(b)
Total number of erasers that Pierre and Wesley had
= 1 u + 21 + 78 + 1 u + 21
= 1 u + 1 u + 21 + 78 + 21
= 2 u + 120
6 u = 2 u + 120
6 u - 2 u = 120
4 u = 120
1 u = 120 ÷ 4 = 30
Total number of erasers that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 30
= 210
Answer(s): (a) 39; (b) 210