Seth bought 58 more buttons than Paul and Paul bought 28 buttons more than Gem. The total number of buttons Seth and Paul bought was 4 times the number of buttons Gem bought.
- How many buttons does Seth need to give Paul so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
Seth |
Paul |
Gem |
1 u + 28 + 58 |
1 u + 28 |
1 u |
4 u |
1 u |
(a)
Number of buttons that Seth needs to give Paul so that they have same number of buttons
= 58 ÷ 2
= 29
(b)
Total number of buttons that Seth and Paul had
= 1 u + 28 + 58 + 1 u + 28
= 1 u + 1 u + 28 + 58 + 28
= 2 u + 114
4 u = 2 u + 114
4 u - 2 u = 114
2 u = 114
1 u = 114 ÷ 2 = 57
Total number of buttons that all three of them had
= 4 u + 1 u
= 5 u
= 5 x 57
= 285
Answer(s): (a) 29; (b) 285