Ivan bought 48 more buttons than Andy and Andy bought 18 buttons more than Usha. The total number of buttons Ivan and Andy bought was 6 times the number of buttons Usha bought.
- How many buttons does Ivan need to give Andy so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
Ivan |
Andy |
Usha |
1 u + 18 + 48 |
1 u + 18 |
1 u |
6 u |
1 u |
(a)
Number of buttons that Ivan needs to give Andy so that they have same number of buttons
= 48 ÷ 2
= 24
(b)
Total number of buttons that Ivan and Andy had
= 1 u + 18 + 48 + 1 u + 18
= 1 u + 1 u + 18 + 48 + 18
= 2 u + 84
6 u = 2 u + 84
6 u - 2 u = 84
4 u = 84
1 u = 84 ÷ 4 = 21
Total number of buttons that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 21
= 147
Answer(s): (a) 24; (b) 147