Jenson bought 76 more buttons than Perry and Perry bought 16 buttons more than Sabrina. The total number of buttons Jenson and Perry bought was 6 times the number of buttons Sabrina bought.
- How many buttons does Jenson need to give Perry so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
Jenson |
Perry |
Sabrina |
1 u + 16 + 76 |
1 u + 16 |
1 u |
6 u |
1 u |
(a)
Number of buttons that Jenson needs to give Perry so that they have same number of buttons
= 76 ÷ 2
= 38
(b)
Total number of buttons that Jenson and Perry had
= 1 u + 16 + 76 + 1 u + 16
= 1 u + 1 u + 16 + 76 + 16
= 2 u + 108
6 u = 2 u + 108
6 u - 2 u = 108
4 u = 108
1 u = 108 ÷ 4 = 27
Total number of buttons that all three of them had
= 6 u + 1 u
= 7 u
= 7 x 27
= 189
Answer(s): (a) 38; (b) 189