Neave and Fred each had the same volume of water. The water was used to pour into identical bottles. Neave filled up 13 bottles and had 6 ℓ of water left. Fred filled up 11 bottles and had 6.26 ℓ of water left.
- What was the capacity of each bottle? Give your answer in millilitres.
- What was the total volume of water Neave and Fred had at first? Give your answer in litres.
(a)
Let 1 B be the volume of 1 bottle of water.
Volume of water that Neave had = 13 B + 6 --- (1)
Volume of water that Fred had = 11 B + 6.26 --- (2)
The volume of water that Neave and Fred have is the same.
(1) = (2)
13 B + 6 = 11 B + 6.26
13 B - 11 B = 6.26 - 6
2 B = 0.26
1 B = 0.26 ÷ 2 = 0.13
1 ℓ = 1000 mℓ
0.13 ℓ = 0.13 x 1000 = 130 mℓ
(b)
Volume of 13 bottles
= 13 x 0.13
= 1.69 ℓ
Volume of water that Neave had at first
= 13 B + 6
= 13 x 0.13 + 6
= 1.69 + 6
= 7.69 ℓ
Total volume of water that Neave and Fred had at first
= 2 x 7.69
= 15.38 ℓ
Answer(s): (a) 130 mℓ; (b) 15.38 ℓ
