Linda had 3 times as many buttons as stickers. After she used 74 buttons and 8 stickers, there were twice as many stickers as buttons.
- How many buttons did Linda have in the end?
- How many stickers did Linda have at first?
| |
Buttons |
Stickers |
Comparing buttons
and stickers at first |
3 p
|
1 p
|
| Before |
1 u + 74 |
2 u + 8 |
| Change |
- 74 |
- 8 |
| After |
1 u |
2 u |
(a)
1 u + 74 = 3 p --- (1)
2 u + 8 = 1 p --- (2)
(2)
x 3
6 u + 24 = 3 p ---(3)
(3) = (1)
6 u + 24 = 1 u + 74
6 u - 1 u = 74 - 24
5 u = 50
1 u = 50 ÷ 5 = 10
Number of buttons that Linda had in the end
= 1 u
= 10
(b)
Number of stickers that Linda had at first
= 2 u + 8
= 2 x 10 + 8
= 20 + 8
= 28
Answer(s): (a) 10; (b) 28
