Andy had an equal number of cream doughnuts, butter doughnuts and chocolate doughnuts. After he ate 28 cream doughnuts, some butter doughnuts and chocolate doughnuts, there were 56 doughnuts left. The number of butter doughnuts he ate was twice the number of chocolate doughnuts he ate. The number of butter doughnuts left was 14 more than the number of cream doughnuts left. How many cream doughnuts were there at first?

	Cream doughnuts	Butter doughnuts	Chocolate doughnuts	Total doughnuts
Before	1 p + 28	1 p + 2 u + 14	1 p + 2 u + 14
Change	- 28	- 2 u	- 1 u
After	1 p	1 p + 14	1 p + 14 + 1 u	56

Number of butter doughnuts and cream doughnuts was equal at first.

1 p + 2 u + 14 = 1 p + 28
2 u = 28 - 14
2 u = 14

1 u = 14 ÷ 2 = 7

Total number of doughnuts in the end
= 1 p + 1 p + 14 + 1 p + 14 + 7
= 1 p + 1 p + 1 p + 14 + 14 + 7
= 3 p + 35

3 p + 35 = 56
3 p = 56 - 35
3 p = 21

1 p = 21 ÷ 3 = 7

Number of cream doughnuts at first
= 1 p + 28
= 7 + 28
= 35

Answer(s): 35